maths.....
If x and y are respectively the 1st and the 2nd terms of an arithmetic sequence,the sum of the first 10 terms is
A.9y - 8x
B.45y - 35x
C.45y - 40x
D.55x - 45y
:confused: B :confused: B :confused:
:icon075: The 2nth term of the geometic sequence:27,-9,3,-1,...is
A.-3^(n-1)
B.-3^(4-n)
C.-3^(4-2n)
D.3^(4-n)
唔識做 :icon064: The 2nth term of the geometic sequence:27,-9,3,-1,...is
A.-3^(n-1)
B.-3^(4-n)
C.-3^(4-2n)
D.3^(4-n)
唔識做 :icon064:
:icon029:
all ans no type wrong:o :icon029:
all ans no type wrong:o
下 :confused: 下 :confused:
有無type 錯d ans:confused::o 有無type 錯d ans:confused::o
哦~冇呀~ 哦~冇呀~
:o
then C :o
then C
點解呢 :D 點解呢 :D
條式=27(-1/3)^n-1 ma ? 條式=27(-1/3)^n-1 ma ?
佢要The 2nth term ? :confused: 佢要The 2nth term ? :confused:
:icon083:
問緊geometic sequence條式 :o :icon083:
問緊geometic sequence條式 :o
咁唔係b咩 :icon009: 咁唔係b咩 :icon009:
:o
你解黎聽下 :( :o
你解黎聽下 :(
我都唔知... :o 我都唔知... :o
咁你列條geometic sequence條式出黎plz:o 咁你列條geometic sequence條式出黎plz:o
27(-1/3)^n-1
=3^3.(-3^-1)^n-1
=3^3.(-3)^1-n
=-3^(4-n)
:confused: 27(-1/3)^n-1
=3^3.(-3^-1)^n-1
=3^3.(-3)^1-n
=-3^(4-n)
:confused:
可以的嗎 :confused:
而且唔係要sub 2n 入去ga mei? 可以的嗎 :confused:
而且唔係要sub 2n 入去ga mei?
係喎... :o
愈黎愈亂添 :(
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