cmh_2002 發表於 2005-4-6 20:02:03

ce maths

煩麻大家...:icon009:

截拳道小子 發表於 2005-4-6 20:08:48

第一題 join AC ...

cmh_2002 發表於 2005-4-6 20:14:05

我都知...之後點?:icon101:

截拳道小子 發表於 2005-4-6 20:17:27

Originally posted by cmh_2002 at 2005-4-6 08:14 PM:
我都知...之後點?:icon101:
:icon083:

BAC = 90
CAQ = CBA

cmh_2002 發表於 2005-4-6 20:23:12

Originally posted by 截拳道小子 at 2005-4-6 08:17 PM:

:icon083:

BAC = 90
CAQ = CBA
第2題呢:(

截拳道小子 發表於 2005-4-6 20:39:35

Originally posted by cmh_2002 at 2005-4-6 08:23 PM:

第2題呢:(
join PQ

BQC 直線

對角 180

X 同 Y

:icon055:
need any explaination ?:icon090:

基維蝦 發表於 2005-4-6 20:46:03

小子又問紫心．．仲諗住冇人識:icon101:

截拳道小子 發表於 2005-4-6 20:47:33

Originally posted by 基維蝦 at 2005-4-6 08:46 PM:
小子又問紫心．．仲諗住冇人識:icon101:

我要睇下紫心係咪掂過2002 :icon035:

紫心兒 發表於 2005-4-6 20:48:39

Originally posted by 截拳道小子 at 2005-4-6 08:47 PM:


我要睇下紫心係咪掂過2002 :icon035:
2002.........:eek:
我都未做過

截拳道小子 發表於 2005-4-6 20:49:54

Originally posted by 紫心兒 at 2005-4-6 08:48 PM:

2002.........:eek:
我都未做過
cmh_2002
:icon055::icon071:


咁你都可以計下ga :icon092:
會考人:icon052:

紫心兒 發表於 2005-4-6 20:51:43

Originally posted by 截拳道小子 at 2005-4-6 08:49 PM:

cmh_2002
:icon055::icon071:


咁你都可以計下ga :icon092:
會考人:icon052:
咁等我睇睇先

紫心兒 發表於 2005-4-6 20:54:08

B^A點解

基維蝦 發表於 2005-4-6 20:59:31

Originally posted by 紫心兒 at 2005-4-6 08:54 PM:
B^A點解

ARC BA:o

紫心兒 發表於 2005-4-6 21:00:05

Originally posted by 基維蝦 at 2005-4-6 08:59 PM:


ARC BA:o
:icon100::icon100:我仲以為打多左.....

基維蝦 發表於 2005-4-6 21:03:11

第一題係咪要計埋度數呀:o

紫心兒 發表於 2005-4-6 21:07:31

係咪咁

基維蝦 發表於 2005-4-6 21:07:56

1.Join line AC,Let PAB be X
Angle BAC =90
Angle PAB = Angle BCA (Angle in alt.segment)
Angle CAQ = Angle CBA (Angle in alt. segment)
Since arc BA =2 arc AC
So, BCA = 2 CBA(arcs prop. to arcs at ce)
IN Tri ABC
BAC+X+1/2X = 180
X=60
So,PAB =60

紫心兒 發表於 2005-4-6 21:17:56

我唔知係唔係咁計

基維蝦 發表於 2005-4-6 21:45:32

Originally posted by 紫心兒 at 2005-4-6 09:17 PM:
我唔知係唔係咁計

邊度有Ｔａｎｇｅｎｔ:icon101:

Tangent Properties都唔係果兩隻equal啦?:o

2076 發表於 2005-4-6 22:41:31

好易wor
成個cyclic quad.係度
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