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發表於 2005-2-13 12:46:46
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ther are 4 kinds of ions in the solution: Cu2+,Cr2O72-,H+,andOH-
according to electrochemical series, Cu2+ and OH- will be discharged.
half equation: Cu2+ +2e- ->2Cu
4OH- ->O2 + 2H2O + 4e-
reddish brown solid will deposit on the cathode, and colourless gas bubbles will be produced on the anode
[ Last edited by martinsy39 on 13-2-2005 at 01:00 PM ] |
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